(4b+7)+(b^2-2b+9)=

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Solution for (4b+7)+(b^2-2b+9)= equation:


Simplifying
(4b + 7) + (b2 + -2b + 9) = 0

Reorder the terms:
(7 + 4b) + (b2 + -2b + 9) = 0

Remove parenthesis around (7 + 4b)
7 + 4b + (b2 + -2b + 9) = 0

Reorder the terms:
7 + 4b + (9 + -2b + b2) = 0

Remove parenthesis around (9 + -2b + b2)
7 + 4b + 9 + -2b + b2 = 0

Reorder the terms:
7 + 9 + 4b + -2b + b2 = 0

Combine like terms: 7 + 9 = 16
16 + 4b + -2b + b2 = 0

Combine like terms: 4b + -2b = 2b
16 + 2b + b2 = 0

Solving
16 + 2b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + 2b + -16 + b2 = 0 + -16

Reorder the terms:
16 + -16 + 2b + b2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 2b + b2 = 0 + -16
2b + b2 = 0 + -16

Combine like terms: 0 + -16 = -16
2b + b2 = -16

The b term is 2b.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2b + 1 + b2 = -16 + 1

Reorder the terms:
1 + 2b + b2 = -16 + 1

Combine like terms: -16 + 1 = -15
1 + 2b + b2 = -15

Factor a perfect square on the left side:
(b + 1)(b + 1) = -15

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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